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Infinity Downline Review Series, Power Of 4 System

For members of Infinity Downline and Infinity 100, this Power of 4 System is essentially a plan of action for creating wealth by defining simple, and easily doable steps for each team member.

The plan dictates a definite predictable result based upon the Power of referring four new people to the program in your first week, and having your down-line members duplicate the same result by referring their first four within their first week and so on.

This system is a function of the Infinity Downline and Infinity 100 compensation plans.

In this program, when one refers their first four members, two of those new people are retained in the referrer's downline and two are passed up to their sponsor.. This is the Two-Up System.

After that, all personal referrals are kept directly in one's own down-line and all enrollees beyond the 4th continue to pay the monthly fee directly to their enroller for as long as they are active in the program.

The Power Of 4 System works out this way:

You sign up four new members to your Infinity Downline or Infinity 100 business in your first week.

Each of your new business partners duplicates this same action by enrolling their first 4 within their first week, and so on down the line.

The pass-ups are happening and the down-line grows as each new member enrolls their 4 people within their first week.

This system does not provide that one must sponsor more than four people. This keeps it very simple.

Running the math for this system you can easily see that one will have created a ongoing monthly residual income of about $12,000 per month within your first eight weeks simply by following this Power Of 4 route. That is for the Infinity Downline program, wherein the monthly commission for each referral is $25. With the Infinity 100 program the commission is $100 per month per referral so you would simply multiply everything by 4.

This is pretty amazing math but the numbers don't lie.

Obviously this is running it with ideal 4 sign ups each week for each person. Evidently every single person is not going to sign up their first 4 people within their first week. Some will enroll 20 and some will enroll none. This is life. Some will never do anything and will never enroll anyone and will quit.

But the ideal, and the agreement which is being sought is that each new prospect, before they join, is "on board" with the Power Of 4 System concept.

It's not a huge goal as 4 is not very many sales.

It is my opinion that if a guy cannot quickly bring at least 4 people into this business, as easy and obviously superior a money-making opportunity as it is, legitimately having no real competition, then that person does not belong in a network marketing business. Twelve years in network marketing and review of hundreds of companies and involvement in many has assured me that there isn't an easier opportunity to build than the Infinity programs. One could argue for or against based on product and opinion and so forth. But in terms of straight dollars measured against effort and time, there isn't anything "easier" out there. Just simple math.

So, admittedly, the Power of 4 System is idealistic and in actuality the outcome will probably not be just as ideal. It is however realistic and quite honestly, 4 people is such a low number to set one's expectation at, that this system appears to me to be utterly over-simple.

If you would like to learn how to completely rule your market in your Infinity business, or any other MLM business, be sure to see the resource area below and follow the links.

About the Author

Get access to free trainings provided by our Infinity Downline and Infinity 100 teams. You can become a high-powered marketing ninja from outer-space, and crush your competition with just a few of these proven methods. Alan Cosens is a 12- yr veteran of this industry.

How to represent this problem as a power series?

How can I represent ʃ(t)/(1-t^8) dt as a power series? I also need to know the radius of convergence for the power series. If it helps, my math book says that the answer is C + Σ(t^8n+2)/(8n+2), and the radius is 1. I just need the intermediate steps to get to this answer. Thanks!

t/(1 - t^8) = t*(1 - t^8)^-1

Use the binomial series for (1 - x)^n with n = - 1 which you can find from many websites. Then replace x by t^8. It will give you a series with powers t^8, t^16, t^24 etc.

Now multiply by the t at the front which makes the series have powers t^9, t^17, t^25 etc. Then integrate the series term by term. This will produce a series with powers t^10, t^18, t^26, etc.

You should now see that the integrated series will have powers which fit the pattern made by t^(8n + 2). The binomial series is only valid for IxI < 1 if n is not a positive integer so this is why the same restriction is applied to t^8 and so to t itself.

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