Lcr Capacitance
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Lcr Capacitance
Second PUC Karnataka Important Physics Questions and Tips
Write Soddy's Group Displacement law.
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Expression for impedance of a series LCR Circuit.
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A question based on series LCR circuit?
An LCR series circuit with a resistance of 50 ohm is connected to AC source of 220V and angular frequency 300 rad/s.When the capacitance alone is removed, the voltage leads the current by 50 degrees & when the inductance alone is removed,the voltage lags behind the current by 50 degrees.Calculate 1)Current 2)power factor 3)the power dissipated in the LCR circuit
since th ephase sift was sysmetric, circuit is in resonance (when LCR).
in that case I=220/50=4.4A, pf=1.00, P=220*4.4=968W.
when one of the LC components is removed, we get 50deg phase shift.
this means that magnitude of the XL or Xc is
|X| = R*tan(50) = 60 Ohm
in that case pf=cos(50)=0.643
and current is smaller because Z=R+iXL or Z=R-iXc
U1700 Series Handheld Capacitance and LCR Meters
