Comp Resistors
2010
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Comp Resistors
What Are The Functions of L6561's Pin
L6561 is the imporved version of the L6560 standard power factor corrector ( Ic components). Fully compatible with the standard verision, I thas a superior performant multiplier making the device capable of working in wide input voltage range applications (from 85V to 265V) with an excellent THD. Furthemore the start up current has been reduces at few tens ofµA and a disable function has been implemented on the ZCD pin, guaranteeing lower current consumption in stand by mode.
L6561 has 8 pins and they have different functions in the circuits. To know the functions of them can be help you if you design a circuit.
Pin Functions of L6561
1 – INV: Inverting input of the error amplifer. A resistive divider is connected between the output regulated voltage and this point, to provide voltage feedback.
2 – COMP: Output of error amplifier. A feedback compensation network is placed between this pin and the INV pin.
3 – MULT: Input of the multiplier stage, A resistive divider connects to this pin the rectifid mains. A voltage signal, proportional to the rectified mains, appears on this pin.
4 – CS: Input to the comparator of the control loop. The current is sensed by a resistor and the resulting voltage is applied to this pin.
5 – ZCD: Zero current detection input. If it si connected to GND, the device is disabled.
6 – GND: Current return for driver and control circuits.
7 – GD: Gate driver output. A push pull output stage is able to drive the power MOS with peak current of 400mA ( source and sink)
8 – Vcc: Supply coltage of driver and control circuits.
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resistor in place of a speaker?
I am looking at hooking up 3 12" Kicker comp subs. i will have 2 running in parallel at 2 ohms each on one amp, but want the 3rd at 2 ohms aswel. is it possible with the 3rd sub, to wire a 4 ohm resistor in parallel to achieve the 2 ohm load on the sub? or will this simply burn out the resistor?
also the amps i have are 300W RMS 2 ch that is 2 ohm stable when bridged, and a 300W mono. is this enough or too much if I am running the 2 subs in parallel as they are 150W RMS at 4 ohms?
i already have the two amps so it will be a pain to get a 1 ohm stable amp. also, the 150RMS is under 4 ohms, it will increase under 2 ohms, and even more under 1 ohm
if i do that 2 subs will be on 2 ohm and 1 on 4 ohm. i don't want this as it will throw out the sound levels and sound off
There are a couple of problems with using a resistor in place of a sub/speaker. The first is that subs are measured by impedance, not resistance. Resistance and impedance are not the same thing.
The bigger problem you will have is that when you use a resistor as described the resistor will consume half of the power (if the impedance was the same for both the sub and resistor). So that means half of the power delivered from your amp will be dissipate across the resistor.
You may think that would work if you only need 150w RMS but the problem is finding a resistor that will actually be able to dissipate that much power. You would need a resistor that can handle the 150-200w RMS that your amp would be providing.
I would suggest either selling your two amps and getting the correct amp or just using the two subs and get rid of the last amp and sub. Or you could just get one more sub and it will work fine.
If your amp is putting out 300w RMS @ 2 ohms and your subs are 150w RMS then that is a perfect setup.
Good Luck!!!
heathkit SB-200 tune up.wmv
